Math, asked by ishita17yashi, 11 months ago

triangle ABC is right angled at b tan A=5 find the value of sec A Sin A+Cot^2A-Cosec^2A

Answers

Answered by raushan6198

0

¹/CosA ×SinA+Cot^2A-(1+Cot^A)

=tanA+Cot^2A-1-Cot^2A

=TànA-1

=5-1

=4 Ans.

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