triangle ABC is right angled at b tan A=5 find the value of sec A Sin A+Cot^2A-Cosec^2A
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¹/CosA ×SinA+Cot^2A-(1+Cot^A)
=tanA+Cot^2A-1-Cot^2A
=TànA-1
=5-1
=4 Ans.
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