Triangle ABC is right-angled at vertex A. Calculate the length of BC, if AB = 8 cm and AC = 6cm
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Answered by
2
Answer:
BY PYTHAGORES THEOREM
AB²+AC²= BC²
8²+6²=BC²
64+36
100=BC²
√100= BC
10cm =Bc
pls mark brainly
Answered by
1
Answer:
Using Pythagoras theorem
BC^2=AC^2+BA^2
let value of BC='x'
then,
x^2=6^2+8^2
x^2=36+64
x^2=100
x=10
BC=10cm
(HERE '^2' represents square)
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