triangle ABC is right angled isosceles triangle at B.Then external angle of A is
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AB=BC
angleBAC=angleBCA
and, angle ABC=90
angle(A+B+C)=180
2C+90=180
c=45
angleDAC=angleABC+angleBCA
angleDAC=135
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Answer: 135°
Step-by-step explanation:
In an Issoceles right angled triangle the acute angles (angles other than the right angle) are equal.
Now, let the each of the equal angles be x.
We have: 90°+x°+x°=180° [Angle Sum Property]
= 90°+2x°=180°
= x°=(180-90)°/2
= x°=45°
Hence measure of angle a and c is 45°.
Measure of angle a = 45°
Measure of angle b = 90°
:: External Angle = a°+b° = 45°+90° = 135°
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