triangle abc is similar to triangle def.area of triangle abc = 49 sqcm and ar( def)= 10 sqcm .ab=12 find de
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GREAT QUESTION
===> WE NEED TO KNOW ONLY A FORMULA
==> AREA OF RATIO OF TWO SIMILAR TRIANGLE IS EQUAL TO SQUARE OF THEIR CORRESPONDING SIDE .
==> SO,
==> AR OF ΔABC / AR OF Δ DEF = (AB/DE)²
==> 49/10 = (12/DE)²
==> √(49/10) = 12/DE
==> √10/7 = DE/12
==> 12√10 /7 = DE
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