Question

triangle ABC is similar to triangle DEF. If ar(triangleABC)= 16/ ar(triangleDEF)= 9 and if AC = 2.4 cm, find the length of side DF.​

Answer 1

Answer:

Given.

Step-by-step explanation:

ar(Triangle ABC) = 16 /Ar of( Triangle DEF) = 9 cm

= 2.4 / DF

= 16/9 = 2.4 / DF

DF = 9× 2.4 / 16

DF = 21.6 / 16

DF = 1.35 cm

Answer 2

${\huge{\underline{\underline{\mathfrak{\texttt{question:-}}}}}}$

triangle ABC is similar to triangle DEF. If ar(triangleABC)= 16/ ar(triangleDEF)= 9 and if AC = 2.4 cm, find the length of side DF.

${\huge{\underline{\underline{\mathfrak{\texttt{answer:-}}}}}}$

GIVEN :- Ar(∆ABC) = 16 cm^2, Ar(∆DEF) = 9cm^2

and ac = 2.1cm

FIND : the length of side DF

we know that the ratio of areas of two similar triangles is equal to the ratio of square of their corresponding sides.

Ar(∆ABC). (AC)^2

---------------. = ------------

Ar(∆DEF). (DF)^2

16. (2.1)^2

---. = ---------

9. (DF)^2

4. 2.1

-- = --------

3. DF

cross multiply ⬆️

6.3 = 4DF

6.3 ÷ 4 = DF

DF = 1.57