Question

triangle ABC is similar to triangle POR.If area of triangle ABC =25, area of triangle PQR =16, find AB:PQ​

Answer 1

Answer:

AB:PQ = 5:4

Step-by-step explanation:

BY RATIO AREA THEOREM

AR ( ABC) /AR(PQR) = (AB/PQ)²

    25/16  = (AB /PQ)²                                

√25/16 =   AB /PQ

5/4 =AB /PQ

 THEREFORE AB:PQ =5 :4

 HOPE SO CORRECT AND HELPFUL !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

 

Answer 2

${\huge {\mathfrak {Answer :-}}}$

✨It is given that $\triangle$ ABC is similar to $\triangle$ PQR.

◾We have,

ar ($\triangle$ ABC) : ar ($\triangle$ PQR) = 25 : 16.

◾AB and PQ are the sides of the respective triangles.

◾Therefore,

AB : PQ = $\sqrt {25}$ : $\sqrt {16}$

= 5 : 4.

✨ Hence, the ratio of the side AB of $\triangle$ ABC to the side PQ of $\triangle$ PQR is 5 : 4.

➡️ $<b>AB : PQ = 5 : 4. </b>$

Done.. ✔️

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