Question

triangle abc is similar to triangle pqr and ar(abc)/ar(pqr)=196/361 then ab/ pq is

Answer 1

Step-by-step explanation:

$Given: \triangle ABC \: similar \: \: \triangle PQR \: \\ hence, by \: area \: of \\ similar \: triangle \: theorem, \: we\: have: \: \\ \frac{A(\triangle ABC)}{A(\triangle PQR)} = ( { \frac{AB}{PQ} })^{2} \: \\ \implies \: \frac{196}{361} = ( { \frac{AB}{PQ} })^{2} \\ \implies \: \sqrt{ \frac{196}{361} } = { \frac{AB}{PQ} } \\ \implies { \frac{AB}{PQ} } = \frac{14}{19}$