Question

triangle ABC is similar to triangle PQR ar(ABC):ar(PQR)=3:4 if PR=4root3 find AC​

Answer 1

Answer :

since the area of two similar triangles are in the ratio of the squares of the corresponding altitudes.

:: Area ( ∆ PQR)

Area ( ∆ ABC)

= PS/2 AD/2

Area(∆PQR)

Area(∆ABC)

= (9/4)2. =81/16

[ :: AD:PS=4:5]

=. Area(∆PQR)

Area (∆ABC)

=AC=81/16