Question

triangle abc is similar to triangle pqr such that ab: pq is 1:3. if perimeter of abc is 15 then find the perimeter of pqr​

Answer 1

Answer:

Let AD be the perpendicular dropped from A to the side BC and PS be the perpendicular dropped from P to the side QR respectively.

Since, ΔABC∼ΔPQR, we have ΔABD∼ΔPQS.

Therefore, PQAB=PSAD=QRBC

⇒arΔPQRarΔABC=PS×QRAD×BC=PQAB×PQAB=PQ2AB2=91





Step-by-step explanation:

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