Question

triangle ABC is similiar to triangle DEF. if the ratio of similiar sides is K:1, the ratio of their areas is
a) k^2:1
b) 2k:1
c) k^2/2:1
d) 2k^2:1
​

Answer 1

Answer:

(a)  k² : 1

Step-by-step explanation:

Given that both triangles are similar, we can apply the similar figure property:

Area1/Area2 = (length 1/length 2)²

We are given that the sides are in the ratio K : 1

Therefore:

Area1/Area2 = (K /1)²

Area1/Area2 = K² / 1

The ratio of area 1 : Area 2 = k² : 1

Answer: (a)  k² : 1