Question

triangle abc is such that ab 3 cm bc 2cm and ca 2.5 cm and def is similar to abc ef 4cm then find the perimeter of def

Answer 1

Answer:

Explanation:n ΔABC

AB = 3 cm

BC = 2 cm

AC = 2.5 cm

Perimeter of triangle = Sum of all sides = 3+2+2.5 = 7.5 cm

Triangle DEF is similar to triangle ABC

Corresponding side of EF in triangle ABC is BC = 2cm

Theorem :The ratio of the sides of similar triangle is equal to the ratio of the perimeter of corresponding triangles

So, Let the perimeter of triangle DEF be x

So,  

Hence perimeter of triangle DEF is 15