triangle abc line ab perpendicular line bc it ab = 9 , bc = 12 then ac
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ab is perpendicular to bc then
it is a right angled triangle
hypotenuse^2 = base^2+ perpendicular^2
(ac)^2 = (bc)^2 + (ab)^2
(ac)^2= 9^2+12^2
(ac)^2 = 81 + 144
(ac)^2 = 225
ac = 15
it is a right angled triangle
hypotenuse^2 = base^2+ perpendicular^2
(ac)^2 = (bc)^2 + (ab)^2
(ac)^2= 9^2+12^2
(ac)^2 = 81 + 144
(ac)^2 = 225
ac = 15
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