triangle ABC~ PQR A(ABC):A(PQR)=1:2 AC=4 then PR=?
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Step-by-step explanation:
ANSWER
Given :
Area of ∆ ABCArea of ∆QRP = 94
AB = 18 cm , BC = 15 cm So PR = ?
We know when two triangles are similar then " The areas of two similar triangles are proportional to the squares of their corresponding sides.
Area of ∆ ABCArea of ∆ QRP = AB2QR2 = Bc2PR2 = AC2QP2
So, we take
Area of ∆ ABC Area of ∆ QRP = BC2PR2
Now substitute all given values and get
94 = 152PR2
Taking square root on both hand side, we get
32 = 15PR
PR = 10 cm
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