Triangle ABC ~ PQR, area of triangle ABC = 225 cm2 and area of triangle PQR = 121cm2. If altitude AD of triangle ABC is 15 cm, then find the altitude of triangle PQR
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Answered by
0
Answer:
ANSWER
We know that the ratio of the areas of two similar triangles is equal to the ratio of the squares of the corresponding sides.
∴
ar(ΔPQR)
ar(ΔABC)
=
QR
2
BC
2
⇒
121
64
=
(15.4)
2
BC
2
⇒
11
8
=
15.4
BC
⇒BC=
11
8×15.4
=11.2cm
Answered by
0
Answer:
Hola...
Step-by-step explanation:
area of triangle PQR/
area of triangle ABC
= PM^2/AD^2
=> 121/81. = PM^2/9^2
=> 121 = PM^2
=> 11cm = PM.
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