triangle ABC right angled at B in which AC is equals to 10 cm ab equals to 8
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Answer:
acc. to Pythagoras theorem:
(AC)²=(AB)²+(BC)²
where given that
AC=10 and AB =8
now putting the value in above equation
(10)²=(8)²+(BC)²
100=64+(BC)²
100-64= (BC)²
36=(BC)²
taking root on both side,we get
√36=√(BC)²
6=BC
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