Triangle abc rt angle at
a. ab=6cm,bc=10cm,is the centre of the circle find area of the in circle
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Since ABC is a rt.∆
AC=√BCsquare-√ABsquare
AC=√10square-√6square
AC=√100-√36
AC=√64
AC=8cm
Therefore area of the rt.∆=1/2×AB×AC
=1/2×6×8cm
=24cm square
AC=√BCsquare-√ABsquare
AC=√10square-√6square
AC=√100-√36
AC=√64
AC=8cm
Therefore area of the rt.∆=1/2×AB×AC
=1/2×6×8cm
=24cm square
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