Question

Triangle ABC similar to triangle d e f and areas are respectively 49 CM square and hundred CM square if d is equal to 17.5 CM then find AB

Answer 1

Step-by-step explanation:

so ans of Ab will be 1.225

Answer 2

$AB=12.25 cm$

Step-by-step explanation:

$\triangle$ABC$\sim\triangle$DEF

Area of triangle ABC=49 square cm

Area of triangle DEF=100 square cm

DE=17.5 cm

When two triangles ABC and DEF are similar  

Then, $\frac{ar(ABC}{ar(DE F)}=(\frac{AB}{DE})^2$

Using the formula  

$\frac{49}{100}=(\frac{AB}{17.5})^2$

$\frac{49}{100}=\frac{AB^2}{(17.5)^2}$

$AB^2=\frac{49\times (17.5)^2}{100}$

$AB=\sqrt{\frac{49\times (17.5)^2}{100}}$

$AB=12.25 cm$

#Learns more:

https://brainly.in/question/15196335:Answered by Aradhana