Triangle ABC similar triangle DEF with AB=BC=3cm,AC =4cm,DE=2fm then EF and DF are respectively
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Since the ratio of areas of two similar triangles is equal to the ratio of the squares of any two corresponding sides.
∴ Area(△DEF)Area(△ABC)=EF2BC2
⇒ Area(△DEF)54=4232
⇒ Area(△DEF)=954×16=96cm2
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