Triangle abc triangle def ar (abc) = 64cm2 and ar (def)= 121cm2.If ef =15.4cm find bc
Answers
Answered by
7
firstly draw two triangles Δand andΔdef.
we know that ratio of areas of two similar triangles is equal to the squares of the corresponding sides of the two given triangles.
therefore:-
ar(abc)/ar(def)=(bc/ef)^2
64/121=(bc/15.4)^2
bc=11.2cm
we know that ratio of areas of two similar triangles is equal to the squares of the corresponding sides of the two given triangles.
therefore:-
ar(abc)/ar(def)=(bc/ef)^2
64/121=(bc/15.4)^2
bc=11.2cm
Answered by
2
Answer:
Answer is 8.145 cm
Step-by-step explanation:
By theorem of class 10 triangles chapter,
ar(abc)/ ar(def) = (bc/ef)^2
64/121 = (bc/15.4)^2
8/11 = bc/15.4
bc = (8 * 15.4)/11
bc= 8 * 1.4
bc = 11.2cm
Similar questions