Math, asked by SumitBattan9560, 1 year ago

Triangle abc triangle def ar (abc) = 64cm2 and ar (def)= 121cm2.If ef =15.4cm find bc

Answers

Answered by Pikes2011
7
firstly draw two triangles Δand andΔdef.
we know that ratio of areas of two similar triangles is equal to the squares of the corresponding sides of the two given triangles.
therefore:-
ar(abc)/ar(def)=(bc/ef)^2
64/121=(bc/15.4)^2
bc=11.2cm
Answered by amruthaabi
2

Answer:

Answer is 8.145 cm

Step-by-step explanation:

By theorem of class 10 triangles chapter,

ar(abc)/ ar(def) = (bc/ef)^2

64/121 = (bc/15.4)^2

8/11 = bc/15.4

bc = (8 * 15.4)/11

bc= 8 * 1.4

bc = 11.2cm

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