Question

Triangle ABC ~ triangle PQR , AB = 4.4 , PQ = 6.6 , BC = 6 , PR = 12 , R , then find QR व AC​

Answer 1

Answer:

Area of triangle =

2

1

× base × height

For base QR=10cm, height PM=4.4cm.

So, area =

2

1

×10×4.4=22cm

2

Let the altitude QN for base PR=11cm, be h.

Area of the triangle will be the same considering any side of the base and its corresponding height.

Hence, area =

2

1

×11×h=22cm

2

=>h=4cm

Answer 2

Answer:

The value of QR = 9 and AC = 8

Step-by-step explanation:

Given,

AB = 4.4

PQ = 6.6

BC = 6

PR = 12

Here,

Triangle ABC ~ Triangle PQR

Therefore, their corresponding sides are proportional.

i.e.,     $\frac{AB}{PQ} = \frac{BC}{QR} = \frac{AC}{PR}$

Now,

Taking    $\frac{AB}{PQ} = \frac{BC}{QR}$

          ⇒  $\frac{4.4}{6.6} = \frac{6}{QR}$

         ⇒ QR × 4.4 = 6 × 6.6

         ⇒ QR = $\frac{39.6}{4.4}$

            ∴ QR = 9

Again

Taking   $\frac{BC}{QR} = \frac{AC}{PR}$

          ⇒ $\frac{6}{9} = \frac{AC}{12}$

          ⇒ AC × 9 = 6 × 12

         ⇒ AC = $\frac{72}{9}$

           ∴ AC = 8