triangle ABC ~ triangle pqr, bc = 4cm, and qr = 7cm, then area of triangle ABC : area of triangle pqr=
Answers
Solution :-
given that,
→ ∆ABC ~ ∆PQR
→ BC = 4 cm
→ QR = 7 cm .
we know that,
- when two ∆'s are similar, ratio of their area = square of there corresponding sides .
So,
→ Area ∆ABC : Area ∆PQR = (AB² : PQ²) = (BC² : QR²) : (AC² : PR²)
putting values of BC and QR,
→ Area ∆ABC : Area ∆PQR = (BC² : QR²)
→ Area ∆ABC : Area ∆PQR = 4² : 7²
→ Area ∆ABC : Area ∆PQR = 16 : 49 (Ans.)
Learn more :-
*जर △ ABC ~ △ DEF असून AB = 12 सेमी and DE = 14 सेमी. तर △ ABC आणि △ DEF यांच्या क्षेत्रफळाचे गुणोत्तर किती?.*
1️⃣ 49/9...
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*In triangle ABC, DE || AB. If CD = 3 cm, EC = 4 cm, BE = 6 cm, then DA is equal to …………….*
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In the figure , Line PQ || Side BC AP = 6 , PB = 8 , AQ = x and QC = 12 , then write the value of x.
https://brainly.in/question/36586072
Answer:
ΔABC ~ ΔPRQ,
PQ is 4 cm, QR is 7 cm, PR is 8 cm
And A(ΔABC)/A(ΔPQR) = 1/4
Concept Used:
When two triangles are similar,
A(Δ ABC)/A(Δ PRQ) = (AB/PR)2 = (BC/RQ)2 = (AC/PQ)2
Calculation:
A(Δ ABC)/A(Δ PRQ) = 1/4
(AC/PQ)2 = 1/4
⇒ AC2/42 = 1/4
⇒ AC2 = 42 × 1/4 = 4
⇒ AC = √4 = 2 cm
∴ Length of AC is 2 cm.
Step-by-step explanation:
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