Question

Triangle ABC ~Triangle PQR then y+z​

Answer 1

Answer:

AS triangle pqr is ≅ triangle abc

by CPCT y=ac

               z=qr

y=4√3

z=6

y+z=6+4√3

Answer 2

GIVEN :-

➪∆ABC ~ ∆PQR

•QR = 6,BC = 8

• PQ = 3 , AB = Z .

• PR=y , AC =4√3

TO FIND :- Value of y+z .

☞︎︎︎CONCEPT:-

By pythagoras theorem,

$\frac{AB}{PQ}$ = $\frac{BC}{ QR }$ = $\frac{AC}{PR}$

SOLUTION:-

$\implies \: \frac{z}{3} = \frac{8}{6} = \frac{4 \sqrt{3} }{y} \\ \\ \implies \: \frac{z}{3} = \frac{8}{6} = > z = \frac{8 \times 3}{6} \\ \\ \implies \: \boxed{z = 4} \\ \\ and \: y \: = \frac{4 \sqrt{3} \times 6}{8} = > 3 \sqrt{3 } \\ \\ \implies \: \boxed{y = 3 \sqrt{3} }$

Now,

$= > y + z = 3 \sqrt{3} + 4$

Hence, the answer is ,

$✪ \boxed{3 \sqrt{3} + 4}$

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HOPE IT HELPS :)