Question

Triangle ABCABCA, B, C has the following vertices: A(-4,6)A(−4,6)A, left parenthesis, minus, 4, comma, 6, right parenthesis B(6,6)B(6,6)B, left parenthesis, 6, comma, 6, right parenthesis C(1,-3)C(1,−3)C, left parenthesis, 1, comma, minus, 3, right parenthesis Is triangle ABCABCA, B, C an equilateral triangle, and why

Answer 1

Answer:

distance between A and B=√(6+4)^2+(6-6)^2

=10

distance between B and C=√(1-6)^2+(-3-6)^2

=√25+81

=√106

AB is not equal to BC

ABC is not equilateral triangle

Answer 2

Answer:

No, triangle ABCABCA, B, C is not an equilateral triangle because \overline{BC

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