Question

triangle ABCD is a rectangle AC equals to 10 cm diagonals AC and BD intersect at P then BP equals to​

Answer 1

Answer:

5 cm

Step-by-step explanation:

Its given that ABCD is a rectangle

diagonal AC = 10 cm

also AC and BD intersect at P

We know that the diagonals of a rectangle are equal in length and bisect each other

therefore AC = BD

BD is bisected by P

BP = 1/2 BD

BP = 1/2 * 10

BP = 5 cm

Answer 2

Answer:

The answer BP = 5 cm

Step-by-step explanation:

Given ABCD is a rectangle

diagonal AC = 10 cm

the diagonals AC and BD are intersecting at P

here we need to find BP  

in a rectangle diagonals are equal then diagonal BD = 10 cm

AC and BD are intersecting at P which will be the mid point of the BD  

therefore P divides BD equally  then BP = 10 /2 = 5 cm