Question

Triangle ABD is right angle at B. on AD there is a point C for which AC=CD and AB=BC then magnigude of angle DAB in degrees

Answer 1

Step-by-step explanation:

60 degrees

As AD=DC (midpoint)

And BD is also equal to AD=DC

This is because a right angle triangle has the property that is

The circumcircle will have the hypotenuse as the diameter ( you can google this if you don't know)

Therefore AD is the radius of the Circle containing ABC i.e AD=CD=BD

So, we also get AB=BD=AD which is an equilateral triangle

Hence anlge CAB = 60 degrees

Answer 2

Answer:

∠$DAB=45^o$

Tip:

Sum of all angles of a triangle is equal to $180^o$

Step

Step 1 of 2:

$ABD$ is an triangle with right angle at $B$.

On $AD$ there is a point $C$ for which $AC=CD$

and $AB=BC$

Here, ∠$ABD=90^o$ ,If $C$ is a midpoint of $AD$ , then it is perpendicular on the line $AD$ and                    

it divides the ∠$ABD$ into two equal angles as ∠$ABC=$∠$CBD=45^o$

Step 2 of 2:

Now we have triangle $ABC$ , having angles

∠$ABC=45^o$

∠$BCA=90^o$

So, ∠$BAC+$∠$ABC+$∠$BCA=180^o$

      ∠$BAC+45^o+90^o=180^o$

      ∠$BAC=180^o-135^o$

      ∠$BAC=45^o$

So, ∠$DAB=45^o$