Question

triangle abocd angle b=3x+10 and angle c =2x find x

Answer 1

Answer:

AB = OA

/_AOB = /_ABO = 3x + 10

/_AOB = /_COD (VERTICALLY OPPOSITE ANGLES)

SO, /_COD = 3X + 10

Using angle sum property in triaNGLE COD

2x + 3x + 10 + 3x + 10 = 180

8x = 160

x = 20

Answer 2

Answer:

The required value $x$ is $20$.

Step-by-step explanation:

Concept:

Having three sides, three angles, and three vertices, a triangle is a closed, two-dimensional object. A polygon also includes a triangle.

Given: triangle abocd angle $b=3x+10$ and angle $c=2x$

To find: The objective is to find out the value of $x$.

Solution:

AB=OA

∠$AOB=$ ∠$ABO$$=3x+10$

∠$AOB=$ ∠$COD$ (VERTICALLY OPPOSITE ANGLES)

So, ∠$COD=3x+10$

Using angle sum property in triaNGLE COD

$2x+3x+10+3x+10=180$

⇒$8x=160$

⇒$x=20$

Therefore, the required value of $x$ is $20$.

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