Question

triangle acb is a right angled triangle at c and CD is perpendicular Ab, if angle b =40 degree, then find angle bac, angle and, angle bcd

Answer 1

2 +5=90 given

6 = 40. given

1+2+5+6=180. asp

1+90+40=180
1=50


in triangle bcd
4=90
6=40
5=?
so 4+5+6=180
90+bcd+40=180
bcd. = 50