Question

triangle and a parallelogram has same base and same area if the sides of triangle are 26 cn 28 cm and 30 cm and the parallelogram stands on the base find the height of parallelogram​

Answer 1

Answer:

Perimeter of Triangle

Perimeter of Triangle2S=26+28+30=84

Perimeter of Triangle2S=26+28+30=84⇒S=42cm

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c)

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c)

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area =

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area = 42(42−26)(42−28)(42−30)

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area = 42(42−26)(42−28)(42−30)

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area = 42(42−26)(42−28)(42−30) =

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area = 42(42−26)(42−28)(42−30) = 42×16×14×12

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area = 42(42−26)(42−28)(42−30) = 42×16×14×12

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area = 42(42−26)(42−28)(42−30) = 42×16×14×12

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area = 42(42−26)(42−28)(42−30) = 42×16×14×12 Area=336cm

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area = 42(42−26)(42−28)(42−30) = 42×16×14×12 Area=336cm 2

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area = 42(42−26)(42−28)(42−30) = 42×16×14×12 Area=336cm 2

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area = 42(42−26)(42−28)(42−30) = 42×16×14×12 Area=336cm 2 Area of parallelogram = Area of triangle

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area = 42(42−26)(42−28)(42−30) = 42×16×14×12 Area=336cm 2 Area of parallelogram = Area of triangle⇒ h×28=336

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area = 42(42−26)(42−28)(42−30) = 42×16×14×12 Area=336cm 2 Area of parallelogram = Area of triangle⇒ h×28=336⇒h=12cm

Perimeter of Triangle2S=26+28+30=84⇒S=42cmArea s(s−a)(s−b)(s−c) (Heron's formula)Area = 42(42−26)(42−28)(42−30) = 42×16×14×12 Area=336cm 2 Area of parallelogram = Area of triangle⇒ h×28=336⇒h=12cmHeight of parallelogram =12cm

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

triangle and a parallelogram has same base and same area if the sides of triangle are 26 cn 28 cm and 30 cm and the parallelogram stands on the base find the height of parallelogram