Question

Triangle APB=~triangleCQD​

Answer 1

Answer:

Proof : (i) In ∆APB and ∆CQD, we have ∠ABP = ∠CDQ [Alternate angles] AB = CD [Opposite sides of a parallelogram] ∠APB = ∠CQD [Each = 90°] ∴ ∆APB ≅ ∆CQD [ASA congruence]

Answer 2

Answer:

Triangle APB=~triangleCQD

Step-by-step explanation:

Triangle APB=~triangleCQD

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