TRIANGLE BAD AND TRIANGLE ADC ARE TWO ISOSCELES TRIANGLES IF ANGLE ABD=64°, FIND ANGLE DAC...
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Answer: ∠DAC= 32°
Step-by-step explanation:
IN ΔABD,
AD = AB
⇒ ∠ABD = ∠ADB = 64°
Now, ∠BDC =180°( LINEAR PAIR)
∠ADC= 180°-64°
∠ADC = 116°
In ΔADC, ∠ADC + ∠DCA + ∠DAC= 180° (ANGLE SUM PROPERTY)
⇒116° + 2( DAC) = 180° ( ∠DAC=∠DCA SINCE AD = DC)
⇒+ 2( DAC) = 180°- 116°
⇒ 2( DAC) = 64°
⇒∠DAC= 32°
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