Triangle D E F is shown. Angle D E F is 90 degrees and angle F D E is 42 degrees. The length of D E is 7.2 and the length of E F is d.
What is the value of d to the nearest hundredth?
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Given : ΔDEF
∠DFE = 90°
∠FDE = 42°
DE = 7.2
EF = d
To Find : value of d to the nearest hundredth
Solution:
ΔDEF
∠DFE = 90°
Hence right angled triangle
Tan ∠FDE = EF/DE
=> Tan 42° = d/7.2
=> d = 7.2 * Tan 42°
=> d = 7.2 * 0.9
=> d = 6.48
value of d to the nearest hundredth = 6.48
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