triangle DEF in which DE=2.2cm , DF= 5.2 cm and angle D=32 dege
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Construct △DEF such that DE=5cm,DF=3cm and m∠EDF=90
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To construct: △DEF where DE=5cm,DF=3cm and m∠EDF=90
o
.
Steps of construction:
(a) Draw a line segment DF=3cm
(b) At point D an angle of 90
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with the help of compass i.e., ∠XDF=90
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.
(c) Taking D as centre, draw an arc of radius 5cm, which cuts DX at the point E
(d) Join EF
It is the required right angle triangle DEF
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