Question

triangle DEF is an equilateral triangle seg DP perpendicular seg EF and E-P-F prove that DP²= 3EP²​.

please answer my question please ​

Answer 1

Answer:

The expression is correct DP^2=3EP^2DP

2 =3EP 2

Step-by-step explanation:

SINCE, the DEF is an equilateral triangle

∴ DE = EF = DF .......eq(1)

NOW,

∵ The DP is perpendicular to EF.

=> The DP is bisecting the side EF.

∴ EP=PF

NOW,

In ΔDEF we have ,

=> DP^2+EP^2=DE^2DP

2 +EP 2 =DE 2

(By pyhtagouros theorom)

=> DP^2+EP^2=EF^2DP

2 +EP 2 =EF 2

( By using eq(1) )

=> DP^2+EP^2=(2EP)^2DP

2 +EP 2 =(2EP) 2

DP 2 +EP 2 =4EP 2

DP 2 =3EP 2

HENCE PROVED DP^2=3EP^2DP

2 =3EP 2

Answer 2

Answer:

Pls mark as brainliest

Step-by-step explanation:

In the pic