Question

Triangle DEF is right angled at E, EG perpendicular to DF & GH perpendicular to EF. Prove- i) GH^2=EH.HF &
ii) EG^=DG.GF ​

Answer 1

Answer:

(2). (1),(2) we get, HF=EG and HF||EG. Similarly we can show that EH=GF and EH||GF . Therefore GEHF is a parallelogram. 7. In triangle ABC, ...

Answer 2

Answer:

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