Triangle EGF is right angled triangle such that angle EFG is 90. EF = 5cm and EG = 13 cm,
then area of triangle EPQ where p and q are the mid-points of EF and EG respectively,is:
I know the answer its 15/2 square cm but I want steps. Please dude answer me.
Answers
Answered by
6
EF=5cm⇒EP=2.5cm (∵ P is midpoint of EF )
EG=13cm⇒EQ=6.5cm (∵ Q is midpoint of EG )
PQ²=(6.5)²-(2.5)²=42.25-6.25=36cm
(∵ EPQ forms a right-angled triangle , right-angled at P)
∴PQ=6cm
Area of ΔEPQ =1/2×bh
= 1/2×6×2.5
= 15/2 cm²
Similar questions