Question

triangle in ratii 3:7:10 show that triangle is right angle

Answer 1

Hi ,

In ∆ABC ,

ratio of angles = 3 : 7 : 10

Let < A = 3x ,

<B = 7x ,

<C = 10x

We know that ,

<A + <B + <C = 180°

[ angle sum Property ]

3x + 7x + 10x = 180°

20x = 180

x = 180/20

x = 9

Therefore ,

<A = 3x = 3 × 9 = 27°

<B = 7x = 7 × 9 = 63°

<C = 10 × 9 = 90°

In ∆ABC , <C = 90°

Therefore ,

∆ABC is a right angled triangle.

I hope this helps you.
: )