Question

triangle is isosceles with ab=ac =7.5 cm and bc = 9 cm the height ad from a

Answer 1

By heron's Formula
We know,
Ar. of isosceles ∆=
$\sqrt{ \frac{a}{2}({x}^{2} - \frac{ {a}^{2} }{4} }$
=√9/2 {(7.5)²-9²/4}

=√4.5 {56.25-81/4}

=√4.5 {56.25-20.25}

=√4.5×36

=76.37cm²(approx.)

Also Ar. of a ∆=1/2×b×h
76.37cm²=1/2×9×h
=>(76.37/9)×2 =h
=>h=16.98cm² (approx.)

Answer 2

Answer:

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Step-by-step explanation:

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × BC × AD

= 1/2 × 9 × 6

= 27 cm²

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × AB × CE

27 cm² = 1/ 2 × 7. 5 × CE

CE = 7.2 CM