Math, asked by shlokbhanushali, 3 months ago

triangle OPQ, angleP=90 ,0P=7 and OQ-PQ =1, find sin O
and cos O​

Answers

Answered by sandhya6075
3

Answer:

Answer

In Δ OPQ, we have

OQ

2

=OP

2

+PQ

2

⇒(PQ+1)

2

=OP

2

+PQ

2

[∵OQ−PQ=1⇒OQ=1+PQ]

⇒PQ

2

+2PQ+1=OP

2

+PQ

2

OP

=

25

7

and, cosQ=

OQ

PQ

=

25

24

Step-by-step explanation:

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