triangle OPQ, angleP=90 ,0P=7 and OQ-PQ =1, find sin O
and cos O
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Answer:
Answer
In Δ OPQ, we have
OQ
2
=OP
2
+PQ
2
⇒(PQ+1)
2
=OP
2
+PQ
2
[∵OQ−PQ=1⇒OQ=1+PQ]
⇒PQ
2
+2PQ+1=OP
2
+PQ
2
OP
=
25
7
and, cosQ=
OQ
PQ
=
25
24
Step-by-step explanation:
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