Triangle POR Q=90,PQ=3,PR=6 FIND ANGLE P ANGLE R
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Given:
PQ = 3 cm
PR = 6 cm
∠Q = 90°.
So this is an right-angled triangle.
By angle sum property,
x + x + 90° = 180°.
2x + 90° = 180°.
2x = 180° - 90°
= 90°.
x = 90° / 2 = 45°.
Therefore, ∠P = 45°
∠R = 45°.
PQ = 3 cm
PR = 6 cm
∠Q = 90°.
So this is an right-angled triangle.
By angle sum property,
x + x + 90° = 180°.
2x + 90° = 180°.
2x = 180° - 90°
= 90°.
x = 90° / 2 = 45°.
Therefore, ∠P = 45°
∠R = 45°.
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