Question

Triangle PQC and Triangle BPQ are alternate angles formed by transversal t to coplanar lines l and m. If

measure of angle PQC = 50, then ______​

Answer 1

Answer:Since, RP is a straight line and ray HD stands on it, then

∠RHD + ∠DHP = 180∘ (angles in a linear pair)

⇒∠RHD + 85∘ = 180∘

⇒∠RHD = 180∘ − 85∘ = 95∘

(ii) Since the straight lines RP and DK intersect at H, then

∠PHG = ∠RHD (Vertically opposite angles)

⇒∠PHG = 95∘

(iii) Since, the line RP || line MS and line DK is their transversal intersecting them at H and G, then

∠HGS = ∠DHP (Corresponding angles)

⇒∠HGS = 85∘

(iv) Since, the straight lines MS and DK intersect at G, then

∠MGK = ∠HGS (Vertically opposite angles)

⇒∠MGK = 85∘

Step-by-step explanation:

Answer 2

Answer:

BPQ and PQC are alternate interior angles on AB and CD when line EF is the transversal. line AB line CD [Alternate angles test] Hence proved. Maharashtra Board Solutions For Class 9 Maths Part 2- Chapter 2 Parallel Lines Problem Set 2.

Step-by-step explanation:

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