Question

triangle PQR, angle Q=90Dree PR=root5unit and PQ - RQ=1unit,cosP-cosR=?​

Answer 1

Step-by-step explanation:

PR+QR=25 (given) and PR=25−QR

5

2

+QR

2

=PR

2

(Pythagorean theorem)

Then substitute PR to get this equation = 5

2

+QR

2

=(25−QR)

2

Solve for QR

5

2

+QR

2

=625−50QR+QR

2

(QR

2

cancels out)

5

2

=625−50QR

−600=−50QR

QR=12

Solve for PR using original equation

PR=13

Now draw the triangle on your paper for help solving the next step

sin=

hyp

opp

⇒sin(P)=

13

12

cos=

hyp

adj

⇒cos(P)=

13

5

tan=

adj

opp

⇒tan(P)=

5

12

D