Question

Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16). What is the y-value of P'?

Answer 1

Answer:

The value of y for P' is -10.

Step-by-step explanation:

The given rule of translation is

$(x,y)\rightarrow (x-2,y-16)$

The vertices of triangle PQR are P(–2, 6), Q(–8, 4), and R(1, –2).

The coordinates of P' are

$P(-2,6)\rightarrow P'(-2-2,6-16)$

$P(-2,6)\rightarrow P'(-4,-10)$

The x-value of P' is -4 and the y-value of P' is -10.