Question

Triangle PQR is a right triangle such that Q=90 A and B are mid points of sides PQ AND QR respectively then PB2+AR2 DIND

Answer 1

(a) RX

2

+PY

2

=(XQ

2

+RQ

2

)+(PQ

2

+QY)

2

=(XQ

2

+QY

2

)+(RQ

2

+QP

2

)

=XY

2

+PR

2

=XY

2

+4XY

2

=5XY

2

(b) From (a), we have XY

2

+PR

2

(c) From (a), we have 4(RX

2

+PY

2

)

=4XY

2

+4PR

2

=PR

2

+4PR

2

=5PR

2