Triangle pqr is an isosceles triangle and ps is altitude on the side of qr.Prove that triangle pqs is congurent to triangle prs
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Ello there!
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Question: ΔPQR is an isoceles triangle and PS is altitude on the side of QR. Prove that ΔPQS ≅ ΔPRS.
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Pre-requisite Knowledge
You must be familiar with concepts related to Congruency, such as
- SSS congruency
- SAS congruency
- ASA conruency
- AAS congruency
- RHS congruency
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Answer
Given,
PQ = QR
PS is an altitude to the side QR
To Prove,
ΔPQS ≅ ΔPRS.
Proof,
In ΔPQS and ΔPRS.
PQ = PR (given)
PS = PS (common side)
∠PSQ = ∠PSR = 90° (Altitude)
∴ ΔPQS ≅ ΔPRS by RHS congruency
(*Remember* RHS cannot be used when we simply obtain an angle is equal to 90°, We must get a Hypotenuse, Altitude and an 90° angle to use RHS congruency)
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