Triangle PQR is an obtuse angled triangle with PR=10cm and obtuse angled at R. From the point P let’s draw a perpendicular PO and QR produced to the pointO, PO=6cm and QO=12cm find the area of triangle PQR
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Answer:
According to Question
`QR^2=PQ^2+PR^2`
`QR^2=10^2+24^2`
`QR^2=100+576=676`
QR=26cm.
Step-by-step explanation:
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