Question

Triangle PQR is right angles isoscles triangle right angled at R find the value of Sin P​

Answer 1

Step-by-step explanation:

sin P =opposite side/hypotenuse

=qr/pq

Answer 2

Answer:

sinP=sin45°=1/√2

Step-by-step explanation:

the triangle is a right angled one

R+P+Q=180°

P+Q=90°

P=Q...........(∆PQR is an isosceles triangle

with opposite sides equal)

90°=2P=2Q

P=Q=45°

sinP = sin45°=1/√2