Question

triangle PQR measure PQR =90 degree and the length of the hypotenuse PR is 13cm find PQ square + QR square. with solution method ​

Answer 1

Given :-

• In ∆PQR , ∠PQR = 90° .
• Hypotenuse PR = 13 cm.

To Find :-

• PQ² + QR² = ?

Solution :-

we know that,

• In a right angled ∆, pythagoras theorem says that, sum of square of base and perpendicular is equal to square of hypotenuse.
• P² + B² = H² .

we have,

• PQ = Perpendicular
• QR = Base .
• PR = Hypotenuse = 13 cm.

so,

→ PQ² + QR² = PR²

→ PQ² + QR² = (13)²

→ PQ² + QR² = 169 (Ans.)

Learn more :-

https://brainly.in/question/36234424

Answer 2

169

is the of following questions