Triangle PQR,Q =90°,PQ=x,QR=y then (sin p ×sin p)+(sin R ×sin R)=
Answers
Answered by
7
Answer:1
Step-by-step explanation:sinp=QR/PR
Sinr=QP/PR
(Sinp×sinp)+(sinr×sinr)
=sin^2p+sin^2r
=(QR/PR)^2+(QP\PR)^2
=QR^2+QP^2/PR^2
=PR^2/PR^2
=1
Similar questions