Question

triangle PQR right angled at R in which hypotenuse PQ is equal to 10 cm side PR is equal to 7 cm

Answer 1

Here, using the pythagoreas theorem.
Another side PR = [(PQ) ^2 - (PR) ^2]^1/2 = (10^2 - 7^2) ^1/2 = (100 - 49) ^1/2 = 51^1/2.
Thus, your answer is root over of 51.

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