Question

triangle PQR, RP = 3cm, PQ = 1cm and angle P is 90°. Find cos R, cot Q, sec R and tan R​

Answer 1

In △PQR,∠PQR=90∘

BY Pythagoras theorem,

PR2=PQ2+QR2

⇒(5)2=PQ2+(4)2

⇒(5)2−(4)2=PQ2

⇒PQ2=25−16

⇒PQ2=9

⇒PQ=9

⇒PQ=3

tanR=QRPQ=43.

Answer 2

Answer:

please see the above attachment